Question

Determine the rate at which the electric field changes between the round plates of a capacitor, 8.0 cm in diameter, if the plates are spaced 1.4 mm apart and the voltage across them is changing at a rate of 110 V/s .

Answer 1

The relation between the potential difference and the electric field between the plates of the parallel plate capacitor is given by :

`$E=(V)/(D)$`

Differentiating on both the sides with respect to time, we get

`$(dE)/(dt)=(1)/(D)(dV)/(dt)$`

Therefore, the rate of the electric field changes between the plates of the parallel plate capacitor is given by :

`$(dE)/(dt)=(1)/(D)(dV)/(dt)$`

`$=(1)/(1.4 * 10^(-3)) * 110$`

`$=7.85 * 10^4$` V/m-s