Question

In the 48 years between 1842, the average rate of erosion at horseshoe falls was 33 divided by 50 metre per year. In the 22 years between 1905 and 1927 the rate of erosion was 7 divided by 10 meter per year . Approximately how much total erosion occurred during these two time periods

Answer 1

47. 08 meters

Explanation:

Given that:

In 48 years between 1842 :

Rate of erosion = 33/50 meters per year

Between 1905 - 1927 (22 years)

Rate of erosion = 7/10 meters per year

Approximately how much total erosion occurred during these two time periods ;

Total erosion that occured within 1842:

Rate of erosion * number of years

(33/50)m * 48

0.66 meters * 48

= 31.68 meters

Total erosion that occured between 1905 - 1927:

Rate of erosion * number of years

(7/10)m * 22

0.7 meters * 22

= 15.40 meters

total erosion which occurred during these two time periods ;

31.68 meters + 15.40 meters

= 47.08 metersStep-by-step explanation:

Answer 2

47. 08 meters

Explanation:

Given that:

In 48 years between 1842 :

Rate of erosion = 33/50 meters per year

Between 1905 - 1927 (22 years)

Rate of erosion = 7/10 meters per year

Approximately how much total erosion occurred during these two time periods ;

Total erosion that occured within 1842:

Rate of erosion * number of years

(33/50)m * 48

0.66 meters * 48

= 31.68 meters

Total erosion that occured between 1905 - 1927:

Rate of erosion * number of years

(7/10)m * 22

0.7 meters * 22

= 15.40 meters

total erosion which occurred during these two time periods ;

31.68 meters + 15.40 meters

= 47.08 meters