Question

At its peak, a tornado is 74.0 m in diameter and carries 335-km/h winds. What is its angular velocity in revolutions per second?

Answer 1

0.399 rev/s

Step-by-step explanation:

Given that,

The diameter of a tornado, d = 74 m

Radius, r = 37 m

Linear velocity, v = 335 km/h = 93.05 m/s

We need to find the angular velocity in revolutions per second. Let it is
`\omega`. The relation between angular velocity and linear velocity is as follows :

`v=r\omega\\\\\omega=(v)/(r)\\\\\omega=(93.0556)/(37)\\\\\omega=2.51\ rad/s`

or

`\omega=(2.51)/(2\pi)\\\\\omega=0.399\ rev/s`

So, the angular velocity of the blade is 0.399 rev/s.