Answer:
Answer: None
Explanation:
Polynomial Remainder Theorem
The polynomial remainder theorem establishes that the remainder of the division of a polynomial f(x) by (x-k) is equal to f(k), that is, substituting x for k.
We are given the polynomial:
![f(x)= x^4+x^3-x^2+x-1](https://img.qammunity.org/2021/formulas/mathematics/high-school/j1bapvcx317r6b8fa43n4aah0ms88p2i5b.png)
And it's required to know if (x+1) and/or (x-1) are factors of the polynomial.
We apply the theorem for both cases.
For (x+1), we substitute x=-1 into the polynomial:
![f(-1)= (-1)^4+(-1)^3-(-1)^2+(-1)-1](https://img.qammunity.org/2021/formulas/mathematics/high-school/non48si75x7tgar8ek49vttqvso4bp7bbj.png)
![f(-1)= 1-1-1-1-1=-3](https://img.qammunity.org/2021/formulas/mathematics/high-school/uvd0fzvdg8lkrdx29evy65qauy0zh5xhia.png)
Since the remainder is not zero, x+1 is not a factor of the given polynomial.
For (x-1), we substitute x=1 into the polynomial:
![f(-1)= (1)^4+(1)^3-(1)^2+(1)-1](https://img.qammunity.org/2021/formulas/mathematics/high-school/56gxmpoapv60te76h8piwpm8m0ieo47n5t.png)
![f(-1)= 1+1-1+1-1=1](https://img.qammunity.org/2021/formulas/mathematics/high-school/dhqtfomwi1uw1b8k7oyfxlxkecgsxl9a07.png)
Since the remainder is not zero, x-1 is not a factor of the given polynomial.
Answer: None