Answer:
3°C
Step-by-step explanation:
Given parameters:
Heat capacity = 300cal
Specific heat capacity = 0.5cal/g°C
Mass of the object = 200g
Initial temperature = 0°C
Unknown:
Final temperature = ?
Solution:
The heat capacity is the amount of heat required to raise the temperature of a substance by 1°C;
Mathematically ;
H = m c x (t₂ - t₁)
H is the heat capacity
m is the mass
c is the specific heat capacity
t is the temperature
Insert the parameters and solve;
300 = 200 x 0.5 x (t₂- 0 )
100 t₂ = 300
t₂ = 3°C