Question

What two steps are necessary to put this equation into standard form
X^2-3x+16=6x-4

Answer 1

The person above is correct, I just checked it

Answer 2

Subtract 6x on both sides

Add 4 on both sides

`x^(2) -9x+20=0`

Explanation:

`x^(2) -3x+16=6x-4\\\\x^(2) -9x+20=0`