Question

A rally car accelerates from 10 m s−1 to 58 m s−1 in 8 seconds as it moves along a straight road. Given that the acceleration is constant, what is the acceleration of the car?

Answer 1

a = 6 [m/s²]

Step-by-step explanation:

To solve this problem we must use the following equation of kinematics

`v_(f) =v_(o) +a*t`

where:

Vf = final velocity = 58 [m/s]

Vo = initial velocity = 10 [m/s]

a = acceleration [m/s²]

t = time = 8 [s]

Now replacing:

58 = 10 + (a*8)

58 - 10 = 8*a

48 = 8*a

a = 6 [m/s²]