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an 11.5g sample of ethonal 6.00g of Carbon 1.51g of hydrogen what is the percent composition of each element

User Mohsan
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1 Answer

6 votes

C : 52.2%, H : 13.1%, O:34.7%

Further explanation

The empirical formula is the smallest comparison of atoms of compound forming elements.

A molecular formula is a formula that shows the number of atomic elements that make up a compound.

(empirical formula) n = molecular formula

11.5 g of Ethanol-C₂H₅OH contains 6.00 g of Carbon and 1.51 g of Hydrogen.

mass of Oxygen :


\tt 11.5-(6+1.51)=4~g

Percent composition :

  • C


\tt (6)/(11.5)* 100\%=52.2\%

  • H


\tt (1.51)/(11.5)* 100\%=13.1\%

  • O


\tt (4)/(11.5)* 100\5=34.7\%

User David Carlisle
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