Question

Solve the following quadratic equation for all value of c i'm simplest form
5(x-2)^2=20

Answer 1

The values of x is 0 and 4.

Explanation:

You have to divide 5 by both sides;

`5 {(x - 2)}^(2) = 20`

`{(x - 2)}^(2) = 4`

You have to expand the brackets;

`{x}^(2) - 4x +4 = 4`

`{x}^(2) - 4 x = 0`

You have to factorize;

`x(x - 4) = 0`

Lastly, you have to solve it;

`x = 0`

`x = 4`

Answer 2

x=-2 and x=0

Explanation:

5(x-2)^2 = 20; divide by 5 both sides

(x-2)^2 = 4; take the square root of both sides

(x-2) = ±2, now set it equal to positive 2 and negative 2

x-2 = 2

x=4

AND

x-2 = -2

x=0