Question

What are the solutions to this quadric equation? -2x^2 + x + 4 = 0

Answer 1

(1-
`√(33)`)/4 and (1+
`√(33)`)/4

Explanation:

-2x^2 + x + 4 = 0

use quadratic formula x= (-b±
`\sqrt{b^(2) -4ac}` ) / 2a

a=-2

b=1

c=4

x= (-1±
`\sqrt{1^(2) -4(-2)(4)}` ) / 2(-2)

x=(-1±
`√(33)` ) / -4

x=(1 -
`√(33)`) / 4 and (1 +
`√(33)`) / 4