Question

In ΔBCD, the measure of ∠D=90°, BC = 81 feet, and DB = 52 feet. Find the measure of ∠C to the nearest tenth of a degree.

Answer 1

39.9

Explanation:

sinC=

sin C = \{52}{81}

sinC=

81

52

​

C=\sin^{-1}{52}{81})

C=sin −1 ( 81 /52 )

C=39.9393\ 39.9^

C=39.9393≈39.9∘

Answer 2

39.9°

Explanation:

m∠C = β

sin β =
`(52)/(81)` ⇒ β = arcsin
`(52)/(81)` ≈ 39.9°