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Line BD is the perpendicular bisector of CA. What additional information would be sufficient to prove that triangle BDA is congruent to triangle BDC by SAS.

User Tirtha R
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1 Answer

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Answer:

DA ≅ DC (since BD is equidistant to A and C)

Step-by-step explanation:

A line bisector is one that divides a given line into two equal parts. And which is equidistant from the ends of the bisected line.

Given: BD is the perpendicular bisector of CA.

Thus:

BD is equidistant to A and C

Also, BD is a common side to ΔBDA and ΔBDC

DA ≅ DC (since BD is equidistant to A and C)

<BDA ≅ <BDC (congruent property)

<ADB ≅ <DBC (alternate angle property)

<CDB ≅ <ABD (alternate angle property)

Thus,

ΔBDA ≅ ΔBDC (Side-Angle-Side, SAS, congruent property)

User ThadeuLuz
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