Question

a train moving at a speed of 15 m/s is accelerated to 45 m/s over a 12 s period. what is the acceleration? ​

Answer 1

2.5 m/s²

Step-by-step explanation:

Given:

v₀ = 15 m/s

v = 45 m/s

t = 12 s

Find: a

a = (v − v₀) / t

a = (45 m/s − 15 m/s) / 12 s

a = 2.5 m/s²