Question

Find the slope of a line perpendicular to a line containing points (3,-5) and (1,7)

Answer 1

Slope of a line perpendicular to a line =
`(1)/(6)`

Explanation:

(x₁ , y₁ ) = (3 , -5) & (x₂, y₂) = (1 , 7)

`slope = (y_(2)-y_(1))/(x_(2)-x_(1))\\`

`= (7-[-5])/(1-3)\\\\=(7+5)/(1-3)\\\\=(12)/(-2)\\\\= - 6`

Slope of the perpendicular line =
`(-1)/(m)`

`= (-1)/(-6)\\\\= (1)/(6)`