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1 vote
Calculate the amount of heat (in kJ) required

to raise the temperature of 250 grams of water
from 30°C to 90°C. (The specific heat of water
is 4.18 J/g.°C.)
Answer in units of kJ.

1 Answer

5 votes
Answer:

=62.7 KJ

Step-by-step explanation:

0.250x4.18x(90-30) = 62.7
User Farini
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