Answer: B. f(x)=(x+4)(x-2)^2(x+3)
Explanation:
in the graph there's two negative x value and one positive x value
so the function should be in a form of f(x)= (x+a) (x-b)^2 (x+c)
the one with negative value has a square, (x-b)^{2}, because that's where the y = 0 (the point is hitting the (x,0))