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20 votes
20 votes
Find two numbers such that their product is four and the sum of their squares is seventeen.

User Splintor
by
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1 Answer

22 votes
22 votes

The system of equations of two unknowns is formulated and solved.


\large\displaystyle\text{$\begin{gathered}\sf \bf{ \left\{\begin{matrix} \ x* y = 4 \\ x^2+y^2 = 17 \end{matrix}\right. \ \Longrightarrow \ y=(4)/(x)} \end{gathered}$}


\large\displaystyle\text{$\begin{gathered}\sf \bf{ x^2+\left ((4)/(x) \right )^2=17\ \Longrightarrow\ x^4+16=17x^2 } \end{gathered}$}


\large\displaystyle\text{$\begin{gathered}\sf \begin{align*} 0&=(x^2)^2-17(x^2)+16\\ =(x^2-16)(x^2-1) \\ \ \ \ \ \ \ \ \ \ \ =(x+4)(x-4)(x+1)(x-1) \end{gathered}$}

Possible number pairs are 4, 1 and -4, -1 .

User Andrew Williamson
by
2.3k points
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