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Find DY divided by DX by implicit differentiation y=sinxy 

User Cristi
by
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Answer:

Explanation:


y = sin(xy)\\(d)/(dx)y=cos(xy)((d)/(dx)(xy))\\ (d)/(dx)y = cos(xy)(y + x*(d)/(dx)y)\\ write \: (d)/(dx)y \: as\:y'\\y' = cos(xy)(y+xy')\\y' = ycos(xy) + xy'cos(xy) \\y'-xy'cos(xy) = ycos(xy)\\y'(1-xcos(xy)) = ycos(xy)\\\\y' = (ycos(xy))/(1-xcos(xy))

User CPJ
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