156k views
6 votes
Find the steady-state charge qp(t), and the steady-state current ip(t),in an LRC-series circuit when

L = 1 h,
R = 4 Ω,
C = 0.1 f, and
E(t) = 30 cos(t) V.

1 Answer

13 votes

Final answer:

The steady-state charge qp(t) and current ip(t) in an LRC-series circuit can be found using the given values of L, R, C, and E(t).

Step-by-step explanation:

In an LRC-series circuit with given values of L, R, C, and E(t), we can find the steady-state charge and current. The steady-state charge, qp(t), is given by the equation q(t) = 90*cos(wt + phi), where w = 1/sqrt(LC) and phi is the phase angle. The steady-state current, ip(t), can be obtained by differentiating the charge equation with respect to time, resulting in i(t) = -90*w*sin(wt + phi).

User ConanG
by
3.9k points