Let a denote the airplane's velocity in the air, g its velocity on the ground, and w the velocity of the wind. (Note that these are vectors.) Then
a = g + w
and we're given
a = (325 m/s) j
w = (55.0 m/s) i
Then
g = - (55.0 m/s) i + (325 m/s) j
The ground speed is the magnitude of this vector:
||g|| = √[ (-55.0 m/s)² + (325 m/s)² ] ≈ 330. m/s
which is faster than the air speed, which is ||a|| = 325 m/s.