I think there's a typo in the question...
Vertically, the box is in equilibrium, so its weight and the normal force (magnitudes w and n, respectively) are such that
n + (-w) = 0
The box has mass 70 kg, and assuming gravitational acceleration with magnitude g = 9.80 m/s², it has a weight of
w = (70 kg) g = 686 N
and hence
n = 686 N
Horizontally, the box is accelerated 3.0 m/s², so the net force acting on it is
∑ F = (70 kg) (3.0 m/s²) = 210 N
and the only forces acting in this dimension are the pulling force with magnitude 130 N and the friction force with magnitude f so that
130 N - f = 210 N
The friction force is proportional to the normal force by a factor of µ, the coefficient of kinetic friction, so that
f = µ n
and so we have
130 N - µ (686 N) = 210 N → µ ≈ -0.117
but µ can't be negative!
The problem is that the pulling force should have a magnitude larger than that of the net force, so either the given mass, acceleration, or pulling force are incorrect.