Question

Help me please my test is tomorrow!​

Answer 1

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`4z + 2 = 10z - 1`

Add sides 1

`4z + 2 + 1 = 10z - 1 + 1`

`4z + 3 = 10z`

Subtract sides 4z

`- 4z + 4z + 3 = - 4z + 10z`

`3 = 6z`

`6z = 3`

Divide sides by 6

`(6z)/(6) = (3)/(6) \\`

`z = (1)/(2) \\`

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`3y = y + 3`

Subtract sides y

`- y + 3y = - y + y + 3`

`2y = 3`

Divide sides by 2

`(2y)/(2) = (3)/(2) \\`

`y = (3)/(2) \\`

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Thus the correct answer is :

`a) \: y = (3)/(2) \: , \: z = (1)/(2) \\`

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