Question

Log_6⁡(x+1)+log_6⁡x=1

Answer 1

This is pretty simple once you figure out the trick.

All you have to do is make the args common.

Meaning
`log_(6)(x + 1) + log_(6)(x) = 1` is nothing but
`log_(6)(x(x + 1)) = 1`

Which is nothing but:
`log_(6)(x^2 + x) = 1`.

Now using the scorpion tail method, this equation can be reframed to being:
`6 = x^2 + x`. You bring 6 to the other side and it'll become:
`x^2 + x - 6 = 0`

Factorise it and you get:
`(x - 2) * (x + 3)`

Henceforth, the solution would be
`2` and
`-3`. :D

Answer 2

D. x = 9

Explanation:

edge 2022