Question

Iron is extracted from iron oxide in the Blast Furnace: Fe 2 O 3 + 3 CO → 2 Fe + 3 CO 2

a) Calculate the maximum theoretical mass of iron that can be made from 100g
of iron oxide.
b) In the reaction, only 65 g of iron was made. Calculate the percentage yield.

Answer 1

a. mass of iron = 69.92 g

b. percent yield = 93%

Further eplanation

Percent yield is the compare of the amount of product obtained from a reaction with the amount you calculated

General formula:

Percent yield = (Actual yield / theoretical yield )x 100%

An actual yield is the amount of product actually produced by the reaction. A theoretical yield is the amount of product that you calculate from the reaction equation according to the product and reactant coefficients

a.

Reaction

Fe₂O₃+3CO⇒2Fe+3CO₂

MW Fe₂O₃ : 159.69 g/mol

mol Fe₂O₃

`\tt (100)/(159,69)=0.626`

mol Fe₂O₃ : mol Fe = 1 : 2

mol Fe :

`\tt (2)/(1)* 0.626=1.252`

mass of Fe(Ar=55.845 g/mol) :

`\tt 1.252* 55.845=69.92~g`

b.

actual yield = 65 g

theoretical yield = 69.92 g

percent yield :

`\tt =(65)/(69.92)=0.93=93\%`