Question

15 points. give me the method.

4.The difference of wavelength of two waves of frequencies 640Hz and 480Hz respectively in a certain medium is 1m. Find the velocity of sound in that medium.

Answer 1

`\boxed{{160 \: m(s)}^( - 1) }`

Step-by-step explanation:

`if \:the \: frequencies \: are \to \\ f_(1) = 640Hz \\ and \\f_(2) = 480Hz \: \\ but \: \boxed{v = f \gamma }: f = (v)/( \gamma ) \\ if \: \gamma_(1) - \gamma _(2) = 1 = \gamma \\ f_(1) - f_(2) = 640 - 480 = \boxed{ 160Hz} = f \\ v = f \gamma = 160 * 1 = \boxed{{160 \: m(s)}^( - 1) }`