Question

Date

Page
1. An organic compound is found to contain the
following constituents :
C = 33.8%. H = 4.7%., N - 13:2%, Cl= 33.4%
and rest is Oxygen. Determine its empirical mass?
​

Answer 1

Emperical formula

C₃H₅NClO

Further explanation

The empirical formula is the smallest comparison of atoms of compound =mole ratio of the components

The principle of determining empirical formula

• Determine the mass ratio of the constituent elements of the compound.
• Determine the mole ratio by by dividing the percentage by the atomic mass

mole ratio :

• C

`\tt (33.8)/(12)=2.82`

• H

`\tt (4.7)/(1)=4.7`

• N

`\tt (13.2)/(12)=1.1`

• Cl

`\tt (33.4)/(35.5)=0.94`

• O

`\tt (14.9)/(16)=0.93`

we divide by the smallest mole ratio (0.93)

C : H : N : Cl : O =

`\tt (2.82)/(0.93)/ (4.7)/(0.93)/ (1.1)/(0.93)/ (0.94)/(0.93)/ (0.93)/(0.93)\\\\3/ 5/ 1/ 1/ 1`

Emperical Formula :

`\tt C_3H_5NClO`