Question

H^6 −64p^6 its trig its factoring the diff/sum of cubes

Answer 1

for example lets say: (x+2)(x-2)(

x

4

+4

x

2

+16)

Rewrte the given terms as perfect cubes as follows and use the algebraic identity for the factorisation of difference of two cubes.

x

6

-64 =

(

x

2

)

3

-

(

4

)

3

=(

x

2

-4) (

x

4

+4

x

2

+16)

=(x+2)(x-2)(

x

4

+4

x

2

+16)

Explanation:

do u think its correct?