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4 votes
H^6 −64p^6 its trig its factoring the diff/sum of cubes

1 Answer

5 votes

Answer:

for example lets say: (x+2)(x-2)(

x

4

+4

x

2

+16)

Rewrte the given terms as perfect cubes as follows and use the algebraic identity for the factorisation of difference of two cubes.

x

6

-64 =

(

x

2

)

3

-

(

4

)

3

=(

x

2

-4) (

x

4

+4

x

2

+16)

=(x+2)(x-2)(

x

4

+4

x

2

+16)

Explanation:

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User Ankit Garg
by
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