The empirical formula : C₁₂H₁₇N₂O₄P
Further explanation
The empirical formula is the smallest comparison of atoms of compound =mole ratio of the components
The principle of determining empirical formula
- Determine the mass ratio of the constituent elements of the compound.
- Determine the mole ratio by by dividing the percentage by the atomic mass
![\tt (50.7)/(12)=4.225](https://img.qammunity.org/2021/formulas/chemistry/college/94uaxt0bous18jjzdsoa9v8su7978hihf2.png)
![\tt (6.03)/(1)=6.03](https://img.qammunity.org/2021/formulas/chemistry/college/w6640ldvbkd2i4p7q8t7fhbqo0w455xpnn.png)
![\tt (9.86)/(14)=0.704](https://img.qammunity.org/2021/formulas/chemistry/college/rrn1ensk97xnpakbbrufeyvn0ld8t5l84e.png)
![\tt (22.51)/(16)=1.407](https://img.qammunity.org/2021/formulas/chemistry/college/q0mgwdwjqhxz1cgiy1aqhrkg5zri9awlpv.png)
![\tt (10.9)/(31)=0.352](https://img.qammunity.org/2021/formulas/chemistry/college/10uvf30rocs1g61damrh3oj32c6g0sf7sq.png)
Divide by the smallest mole ratio(0.352)
C : H : N : O : P
![\tt C\rightarrow (4.225)/(0.352)=12](https://img.qammunity.org/2021/formulas/chemistry/college/enp8y1sop8vf3lxxfgum2bn8taqhje99sq.png)
![\tt H\rightarrow (6.03)/(0.352)=17](https://img.qammunity.org/2021/formulas/chemistry/college/juo1sglto2whskqqx6026yvk93ijrurtma.png)
![\tt N\rightarrow (0.704)/(0.352)=2](https://img.qammunity.org/2021/formulas/chemistry/college/fzvd0t8m4ro0g37m7rrnv11xjgzdl5jclc.png)
![\tt O\rightarrow (1.407)/(0.352)=4](https://img.qammunity.org/2021/formulas/chemistry/college/saib7qxvgdvpeqyefifisdjsl02gr0oz3c.png)
![\tt P\rightarrow (0.352)/(0.352)=1](https://img.qammunity.org/2021/formulas/chemistry/college/9gsyj77zri9s58kz51mn02iph0nqlzpuch.png)