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What volume of a 0.295 M nitric acid solution is required to neutralize 24.8 mL of a 0.107 M potassium hydroxide solution
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What volume of a 0.295 M nitric acid solution is required to neutralize 24.8 mL of a 0.107 M potassium hydroxide solution

User Adizbek Ergashev
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1 Answer

10 votes

Answer: 9.00 mL

Step-by-step explanation:


M_(A)V_(A)=M_(B)V_(B)\\(0.295)V_(A)=(0.107)(24.8)\\V_(A)=((0.107)(24.8))/((0.295)) \approx \boxed{9.00 \text{ mL}}

What volume of a 0.295 M nitric acid solution is required to neutralize 24.8 mL of-example-1
User Alex Lord Mordor
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