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6y+4−3y−7=3(y−1) How many solutions are for this?

User Sgliser
by
4.9k points

2 Answers

1 vote

No solutions.

General Formulas and Concepts:

Order of Operations: BPEMDAS

Regular + Equality Properties

Step-by-step explanation:

Step 1: Define equation

6y + 4 - 3y - 7 = 3(y - 1)

Step 2: Solve for y

Combine like terms: 3y - 3 = 3(y - 1)

Distribute 3: 3y - 3 = 3y - 1

Subtract 3y on both sides: -3 ≠ -1

Here we see that there will be no solutions of y.

User Amogh Natu
by
4.9k points
0 votes

Answer:

Infinite amount of solutions.

General Formulas and Concepts:

  • Order of Operations: BPEMDAS
  • Regular + Equality Properties

Explanation:

Step 1: Define equation

6y + 4 - 3y - 7 = 3(y - 1)

Step 2: Solve for y

  1. Combine like terms: 3y - 3 = 3(y - 1)
  2. Distribute 3: 3y - 3 = 3y - 3
  3. Subtract 3y on both sides: -3 = -3

Here we see that there will be infinite amount of solutions. We can plug in any number y and it will render the equation true.

User Sureone
by
4.8k points