Question

In the Bohr model of the atom, atomic electrons approximatately 'orbit' the nucleus. The hydrogen atom consists of a proton of mass 1.67 × 10-27 kg and an orbiting electron of mass 9.11 × 10-31 kg. In one of its orbits, the electron is 5.3 × 10-11 m from the proton. What is the mutual attractive gravitational force between the electron and proton

Answer 1

`F=3.61* 10^(-47)\ N`

Step-by-step explanation:

Mass of a proton,
`m_p=1.67* 10^(-27)\ kg`

Mass of an electron,
`m_e=9.11* 10^(-31)\ kg`

The distance between the electron and the proton is,
`r=5.3* 10^(-11)\ m`

We need to find the mutual attractive gravitational force between the electron and proton. The gravitational force is given by :

`F=G(m_em_p)/(r^2)`

Where G is the universal Gravitational constant

`F=6.67* 10^(-11)* (9.11* 10^(-31)* 1.67* 10^(-27))/((5.3* 10^(-11))^2)\\\\F=3.61* 10^(-47)\ N`

So, the force between the electron and proton is
`3.61* 10^(-47)\ N`.