Question

A force of 6.00 N acts in the positive direction on a 3.00 kg object, originally traveling at +15.0 m/s, for 10.0 s. (a) What is the object’s change in momentum?

Answer 1

60 kg m/s

Step-by-step explanation:

F= Force = 6 N

m = Mass of object = 3 kg

u = Initial velocity = 15 m/s

t = Time = 10 s

v = Final velocity

`\Delta p` = Change in momentum

Force is given by

`F=(\Delta p)/(t)\\\Rightarrow Ft=\Delta p\\\Rightarrow \Delta p=6* 10\\\Rightarrow \Delta p=60\ \text{Ns}`

The change in momentum of the object is 60 kg m/s.