115k views
1 vote
Please helpp middle school math

suppose 4<a<7. find all the possible values of 15-2a​

User Kryptonkal
by
5.8k points

1 Answer

3 votes

9514 1404 393

Answer:

1 < 15 -2a < 7

Explanation:

There are a couple of ways you can do this.

1) Put the minimum and maximum values of a into the expression to see what its corresponding values are:

15-2a for a=4:

15-2(4) = 7

15-2a for a=7:

15-2(7) = 1

Then ...

1 < 15-2a < 7

__

2) Solve for a in terms of the value of 15-2a, then impose the limits on a.

x = 15 -2a

2a = 15 -x

a = (15 -x)/2

Now, impose the given limits:

4 < (15 -x)/2 < 7

8 < 15 -x < 14 . . . multiply by 2

-7 < -x < -1 . . . . . . subtract 15

7 > x > 1 . . . . . . . . multiply by -1

1 < 15-2a < 7 . . . . . use x=15-2a

_____

The vertical extent of the attached graph is the range of possible values of 15-2a. It goes from 1 to 7.

Please helpp middle school math suppose 4<a<7. find all the possible values-example-1
User Caleb Gray
by
5.6k points