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4 votes
Solve for z.
12 = 15(z-1/5

1 Answer

5 votes

Answer:

z= 1

Explanation:

Rewrite the equation as

15(z−1/5)z12

Apply the distributive property

15z+15(−1/5)= 12

Cancel the common factor of 5

15z+3*−1= 12

Multiply 3 by −1

15z−3= 12

Divide each term by 15 and simplify

5z−1 = 4

Since the expression on each side of the equation has the same denominator, the numerators must be equal

5z−1= 4

Move all terms not containing z to the right side of the equation

5z= 5

Divide each term by 5 and simplify

z = 1

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