Question

7. Write the equation for the positron emission of barium-127.

Answer 1

`\sf {}^(127)_(56)Ba\longrightarrow {}^0_(1)\beta+{}^(127)_(55)Cs`

Remember

• Radioactive decays are first order reactions
• The rate constant doesn't depend upon initial concentration
• It's never ending reaction

Answer 2

The reaction is given by

`\\ \rm\Rrightarrow {}^(127)_(56)Ba\longrightarrow {}^(0)_(+1)\beta+{}^(127)_(55)Cs`

Barium goes underneath beta decay to form Ceaseum

• Cs is very mellable element
• It can melt on your hand