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What is the sum of all integers that are multiples of 4 from 1 to 150? *Show your solution*

User Rhen
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There's a pretty simple formula to follow: count of multiples
* average of the multiple.

To find the average, we take the smallest multiple of 4 which is in the range of 1 and 150 which is 4 of course. And the largest would be 148 since that's the only number in the range. So now average them:
(4 + 148)/(2) = (152)/(2) = 76

Now we find the count of the multiples which is in the range of 1 to 150. To do that, we use this formula:


\frac{\text{largest multiple} - \text{smallest multiple}}{n} \\

Here,
n is 4 so this would be:


(148-4)/(4) = (144)/(4) = 36

This would give you the exclusive count of all the numbers, but we want the inclusive count so, we simple add 1 so the count would be
37

Now following the 1st formula we get:
37 * 76 = 2812

So the answer would be 2812! :D

And here's the check too:

What is the sum of all integers that are multiples of 4 from 1 to 150? *Show your-example-1
User Punam
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