There's a pretty simple formula to follow: count of multiples
average of the multiple.
To find the average, we take the smallest multiple of 4 which is in the range of 1 and 150 which is 4 of course. And the largest would be 148 since that's the only number in the range. So now average them:
![(4 + 148)/(2) = (152)/(2) = 76](https://img.qammunity.org/2021/formulas/mathematics/high-school/emgyosv932hqsfc65dlvr833xjd0xprtq6.png)
Now we find the count of the multiples which is in the range of 1 to 150. To do that, we use this formula:
![\frac{\text{largest multiple} - \text{smallest multiple}}{n} \\](https://img.qammunity.org/2021/formulas/mathematics/high-school/hivp9k3vdk0pytm8ewzpmpa117nlbchdlq.png)
Here,
is 4 so this would be:
![(148-4)/(4) = (144)/(4) = 36](https://img.qammunity.org/2021/formulas/mathematics/high-school/8af8j82kaasn1ydssdk1w2v0xhpht2dt5o.png)
This would give you the exclusive count of all the numbers, but we want the inclusive count so, we simple add 1 so the count would be
![37](https://img.qammunity.org/2021/formulas/chemistry/middle-school/y00o00voqvh5agmjfauea9n7bv9f3dwjfv.png)
Now following the 1st formula we get:
![37 * 76 = 2812](https://img.qammunity.org/2021/formulas/mathematics/high-school/3w1zw1qtpybqopf75896ukp0fbnr3aoagr.png)
So the answer would be 2812! :D
And here's the check too: