What is the solution to the system of equations?

Question

asked Jan 15, 2021 174k views

1 Answer

Plamb · Answer 1 · 2021-01-20T10:17:18+0000

Answer:

No solution

Explanation:

$-3x-4y-3z=-7\\2x-6y+2z=3\\5x-2y+5z=9\\\\$

Lets consider the equation 2.

Here we multiply the LHS and RHS with (-1).

$-3x-4y-3z=-7\\-(2x-6y+2z)=-3\\5x-2y+5z=9\\\\$

Hence,

$-3x-4y-3z=-7\\-2x+6y-2z=-3\\5x-2y+5z=9\\\\$

When we add the equations we get,

$0x+0y+0z=-10+9\\Hence,\\0=-1$

As 0 doesn't equal to -1, answer is d) No solution