Question

What is the solution to the system of equations?

Answer 1

No solution

Explanation:

`-3x-4y-3z=-7\\2x-6y+2z=3\\5x-2y+5z=9\\\\`

Lets consider the equation 2.

Here we multiply the LHS and RHS with (-1).

`-3x-4y-3z=-7\\-(2x-6y+2z)=-3\\5x-2y+5z=9\\\\`

Hence,

`-3x-4y-3z=-7\\-2x+6y-2z=-3\\5x-2y+5z=9\\\\`

When we add the equations we get,

`0x+0y+0z=-10+9\\Hence,\\0=-1`

As 0 doesn't equal to -1, answer is d) No solution