Question

Any help? Much appreciated ​

Answer 1

`(6+√(27) )/(4-√(3) ) = (r+s√(3) )/(13) \\We\ may\ multiply\ the\ numerator\ and\ denominator\ with\ (4+√(3) ).\\Hence,\\((6+√(27))(4+√(3)) )/(13) = (r+s√(3) )/(13) \\Hence,\\24+6√(3) +4√(27) +9= r+s√(3)\\24+6√(3) +4*3√(3) } +9= r+s√(3)\\24+6√(3) +12√(3)+9 = r+s√(3)\\33+18√(3) = r+s√(3)\\Hence,\\r=33, s=18`