Question

Find the equationof a circle whose centre is (-3-15) and passing point (5,-1) find the equation of circle..​

Answer 1

Answer:
`(x+3)^(2) +(y+15)^(2)=260`

Explanation:

The centre is (-3,-15), so we can say the equation of circle is
`(x+3)^(2) +(y+15)^(2)=r^(2)`. put (5,-1) at this equation.

then, we can know
`r^(2)=260`.

∴
`(x+3)^(2) +(y+15)^(2)=260`