Question

1. Consider the reaction of magnesium metal with hydrochloric acidity produce magnesium chloride and hydrogen gas. If 36.03g of magnesium and 55.10g of hydrochloric are reacted , how many grams of hydrogen gas are produced?

2. How many magnesium chloride are formed from the previous reaction?

Answer 1

Mass magnesium chloride produced = 71.88g

Mass of hydrogen gas produced = 1.51 g

Step-by-step explanation:

Given data:

Mass of magnesium = 36.03 g

Mass of HCl = 55.10 g

Mass of hydrogen gas produced = ?

Mass of magnesium chloride produced = ?

Solution:

Chemical equation:

Mg + 2HCl → MgCl₂ + H₂

Number of moles of Mg:

Number of moles = mass/molar mass

Number of moles = 36.03 g/ 24.3 g/mol

Number of moles = 1.48 mol

Number of moles of HCl:

Number of moles = mass/molar mass

Number of moles = 55.10 g/ 36.5 g/mol

Number of moles = 1.51 mol

Now we will compare the moles of hydrogen and magnesium chloride with HCl and Mg.

Mg : H₂

1 : 1

1.48 : 1.48

HCl : H₂

2 : 1

1.51 : 1/2×1.51 = 0.755

Mass of hydrogen:

Mass = number of moles × molar mass

Mass = 0.755mol × 2 g/mol

Mass = 1.51 g

Mg : MgCl₂

1 : 1

1.48 : 1.48

HCl : MgCl₂

2 : 1

1.51 : 1/2×1.51 = 0.755

Mass of magnesium chloride:

Mass = number of moles × molar mass

Mass = 0.755mol × 95.211g/mol

Mass = 71.88g