Question

What is the equation of a line that passes through (-6, 2) and has a slope of `-(1)/(2)'?

OA.
'y = (x)/(2)-2
'y=-(x)/(2)-1
OB.
O c.
'y = 2x +11
OD.
‘y = -2x-1

Answer 1

y =
`-(1)/(2)` x + 5

Explanation:

Given parameters:

Coordinates = (-6,2)

Slope =
`-(1)/(2)`

Unknown:

Equation of the line that passes through = ?

Solution:

The equation of a line is expressed as;

y =mx + c

y and x are the coordinates

m is the slope

c is the y-intercept

let us find c;

2 =
`-(1)/(2)` x 6 + c

2 = -3 + c

c = 5;

The equation of the line is;

y =
`-(1)/(2)` x + 5