Question

Solve the right triangle

Answer 1

JK = 50; IJ = 25√3

Explanation:

HAVE: sin ∠J = sin 30° =
`(IK)/(JK)`

=>
`(IK)/(JK)=(25)/(JK)=(1)/(2)=> JK = 25.2 = 50`

cos ∠J = cos 30° =
`(IJ)/(JK)`

=>
`(IJ)/(JK)=(IJ)/(50)=(√(3) )/(2) => IJ = (√(3) )/(2).50=25√(3)`