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Write the equation of a line perpendicular to 5x - 7y =-6 that passes through the point (-5,6)

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Answer:

7x +5y = -5

Explanation:

You can find the perpendicular line by swapping the x- and y-coefficients, and negating one of them. The new constant can be found by using the given point.

7x +5y = 7(-5) +5(6) = -5

The perpendicular line through (-5, 6) is ...

7x +5y = -5

Write the equation of a line perpendicular to 5x - 7y =-6 that passes through the-example-1
User BjoernD
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