98.0k views
4 votes
Given that sin θ = 3/4 and θ is in Quadrant II:
Find cos θ.

1 Answer

6 votes

this is for the Sin

*Remember that sin = opposite / hypotenuse*

a² + b² = c² (where a and b are legs and c is the hypotenuse)

From the picture, you can see:

a = 3

c = 4

Plug these into the equation and solve for b.

* a² + b² = c² *

step 1: 3² + b² = 4²

step 2: 9 + b² = 16

step 3: b² = 16 - 9

step 4: b² = 7

step 5: √(b²) = √7

step 6: b = ± √7

FOR COS:

From the picture, you can see that if θ is in quadrant II, b has to be negative.

b = -√7 = adjacent

Remember that cos θ = adjacent / hypotenuse.

cos θ = adjacent / hypotenuse

cos θ = (-√7 / 4)

User Cisum Inas
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories