Question

Grade 11 Algebra 2

Can any one please help me with this Algebra 2 math problem. Soon as possible!

Write an equation in slope-intercept form for the line that passes through (–2, 1) and is parallel to the line whose equation is 3x + 2y = 6.

Show all work.

Answer 1

y=-3/2x-2

Explanation:

simplify 3x+2y=6 first

-3x. -3x

2y= -3x+6

Divide by 2

y= -3/2x+3

since it's parallel you would use the same slope

slope= -3/2x

Now you need to find b (x-intercept)

point (-2,1)=(x,y) use this to plug into y=mx+b

=

(1)=-3/2(-2)+b (simplify)

1 = 3+b

-3 -3

-2= b

so put it together and get

y=-3/2x-2