menu
Qammunity.org
Login
Register
My account
Edit my Profile
Private messages
My favorites
6x + 21y = 103 -6x + 23y = 51
Ask a Question
Questions
Unanswered
Tags
Ask a Question
6x + 21y = 103 -6x + 23y = 51
asked
Jan 9, 2021
128k
views
3
votes
6x + 21y = 103
-6x + 23y = 51
Mathematics
high-school
Malangi
asked
by
Malangi
8.2k
points
answer
comment
share this
share
0 Comments
Please
log in
or
register
to add a comment.
Please
log in
or
register
to answer this question.
1
Answer
4
votes
Hope that helps you :))
Spencer Ruport
answered
Jan 14, 2021
by
Spencer Ruport
8.7k
points
ask related question
comment
share this
0 Comments
Please
log in
or
register
to add a comment.
← Prev Question
Next Question →
Related questions
asked
Dec 7, 2022
224k
views
What’s the system for 5x+21y=103 and -5x+23y=29
Vikram Singh
asked
Dec 7, 2022
by
Vikram Singh
8.2k
points
Mathematics
high-school
1
answer
2
votes
224k
views
asked
Sep 26, 2024
105k
views
5[3(23y) 2(5- y)] 6[5(y-2) - 2(4y - 3)] < 3y + 19
Matthew Coelho
asked
Sep 26, 2024
by
Matthew Coelho
9.1k
points
Mathematics
high-school
1
answer
4
votes
105k
views
asked
Jan 27, 2024
40.0k
views
:) Find the numbe bases X and y from the following simultaneous equations 25x- 23y=10 34x+32y =36
Vural
asked
Jan 27, 2024
by
Vural
8.4k
points
Mathematics
high-school
1
answer
4
votes
40.0k
views
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.
9.4m
questions
12.2m
answers
Categories
All categories
Mathematics
(3.7m)
History
(955k)
English
(903k)
Biology
(716k)
Chemistry
(440k)
Physics
(405k)
Social Studies
(564k)
Advanced Placement
(27.5k)
SAT
(19.1k)
Geography
(146k)
Health
(283k)
Arts
(107k)
Business
(468k)
Computers & Tech
(195k)
French
(33.9k)
German
(4.9k)
Spanish
(174k)
Medicine
(125k)
Law
(53.4k)
Engineering
(74.2k)
Other Questions
How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Twitter
WhatsApp
Facebook
Reddit
LinkedIn
Email
Link Copied!
Copy
Search Qammunity.org