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What volume of a 0.252 M hydroiodic acid solution is required to neutralize 18.0 mL of a 0.151 M barium hydroxide solution

User Laetis
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Answer: 10.8 M

Step-by-step explanation:


M_(A)V_(A)=M_(B)V_(B)\\(0.252)V_(A)=(18.0)(0.151)\\V_(A)=((18.0)(0.151))/((0.252)) \approx \boxed{10.8 \text{ M}}

What volume of a 0.252 M hydroiodic acid solution is required to neutralize 18.0 mL-example-1
User GIJOW
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