Question

What is an equation of the line that passes through the point (-5,-4) and is perpendicular to the line 5x+6y=36

Answer 1

y = 6/5x + 2

Explanation:

First let's fix this equation

5x + 6y = 36 (subtract 5x on both sides)

6y = -5x + 36 (divide by 6 on both sides)

y = -5/6x + 6

NOW

The perpendicular slope of this equation is 6/5

Now we have to plug in (-5,-4) to get the y-intercept

-4 = 6/5(-5) + b (distribute 6/5 to -5) (b represents the y-intercept)

-4 = -6 + b (add 6 on both sides)

2 = b

So your equation is...

y = 6/5x + 2

HOPE THIS HELPED!!!!!