Question

A 350 mL air sample collected at 308 K has a pressure of 73 kPa. What

will be the pressure of the sample if it is allowed to expand to 425 mL at
333K?

Answer 1

65 kPa

Step-by-step explanation:

Step 1: Given data

• Initial pressure (P₁): 73 kPa

• Initial volume (V₁): 350 mL

• Initial temperature (T₁): 308 K

• Final pressure (P₂): ?

• Final volume (V₂): 425 mL

• Final temperature (T₂): 333 K

Step 2: Calculate the final pressure of the air sample

If we assume an ideal gas behavior, we can calculate the final pressure of the air sample using the combined gas law.

P₁ × V₁/T₁ = P₂ × V₂/T₂

P₂ = P₁ × V₁ × T₂/T₁ × V₂

P₂ = 73 kPa × 350 mL × 333 K/308 K × 425 mL

P₂ = 65 kPa