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What is the specific heat of a substance that absorbs 1000 joules of heat when a sample of 25 g of the substance increases in temperature from 10.0C to 60.0C

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Answer:

1250000

Step-by-step explanation:

Specific heat is mass times specific heat capacity times change in temperature to get chance in temperature minus the old temperature from the new temperature then complete equation hence 25g×1000j×(60-10)

25g×1000j×50

=1250000g/j/degree Celsius

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